Optimal. Leaf size=281 \[ -\frac {7 e (4 b B d-9 A b e+5 a B e)}{20 b (b d-a e)^3 (d+e x)^{5/2}}-\frac {A b-a B}{2 b (b d-a e) (a+b x)^2 (d+e x)^{5/2}}-\frac {4 b B d-9 A b e+5 a B e}{4 b (b d-a e)^2 (a+b x) (d+e x)^{5/2}}-\frac {7 e (4 b B d-9 A b e+5 a B e)}{12 (b d-a e)^4 (d+e x)^{3/2}}-\frac {7 b e (4 b B d-9 A b e+5 a B e)}{4 (b d-a e)^5 \sqrt {d+e x}}+\frac {7 b^{3/2} e (4 b B d-9 A b e+5 a B e) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{4 (b d-a e)^{11/2}} \]
[Out]
________________________________________________________________________________________
Rubi [A]
time = 0.17, antiderivative size = 281, normalized size of antiderivative = 1.00, number of steps
used = 7, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {79, 44, 53, 65,
214} \begin {gather*} \frac {7 b^{3/2} e (5 a B e-9 A b e+4 b B d) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{4 (b d-a e)^{11/2}}-\frac {7 b e (5 a B e-9 A b e+4 b B d)}{4 \sqrt {d+e x} (b d-a e)^5}-\frac {7 e (5 a B e-9 A b e+4 b B d)}{12 (d+e x)^{3/2} (b d-a e)^4}-\frac {7 e (5 a B e-9 A b e+4 b B d)}{20 b (d+e x)^{5/2} (b d-a e)^3}-\frac {5 a B e-9 A b e+4 b B d}{4 b (a+b x) (d+e x)^{5/2} (b d-a e)^2}-\frac {A b-a B}{2 b (a+b x)^2 (d+e x)^{5/2} (b d-a e)} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 44
Rule 53
Rule 65
Rule 79
Rule 214
Rubi steps
\begin {align*} \int \frac {A+B x}{(a+b x)^3 (d+e x)^{7/2}} \, dx &=-\frac {A b-a B}{2 b (b d-a e) (a+b x)^2 (d+e x)^{5/2}}+\frac {(4 b B d-9 A b e+5 a B e) \int \frac {1}{(a+b x)^2 (d+e x)^{7/2}} \, dx}{4 b (b d-a e)}\\ &=-\frac {A b-a B}{2 b (b d-a e) (a+b x)^2 (d+e x)^{5/2}}-\frac {4 b B d-9 A b e+5 a B e}{4 b (b d-a e)^2 (a+b x) (d+e x)^{5/2}}-\frac {(7 e (4 b B d-9 A b e+5 a B e)) \int \frac {1}{(a+b x) (d+e x)^{7/2}} \, dx}{8 b (b d-a e)^2}\\ &=-\frac {7 e (4 b B d-9 A b e+5 a B e)}{20 b (b d-a e)^3 (d+e x)^{5/2}}-\frac {A b-a B}{2 b (b d-a e) (a+b x)^2 (d+e x)^{5/2}}-\frac {4 b B d-9 A b e+5 a B e}{4 b (b d-a e)^2 (a+b x) (d+e x)^{5/2}}-\frac {(7 e (4 b B d-9 A b e+5 a B e)) \int \frac {1}{(a+b x) (d+e x)^{5/2}} \, dx}{8 (b d-a e)^3}\\ &=-\frac {7 e (4 b B d-9 A b e+5 a B e)}{20 b (b d-a e)^3 (d+e x)^{5/2}}-\frac {A b-a B}{2 b (b d-a e) (a+b x)^2 (d+e x)^{5/2}}-\frac {4 b B d-9 A b e+5 a B e}{4 b (b d-a e)^2 (a+b x) (d+e x)^{5/2}}-\frac {7 e (4 b B d-9 A b e+5 a B e)}{12 (b d-a e)^4 (d+e x)^{3/2}}-\frac {(7 b e (4 b B d-9 A b e+5 a B e)) \int \frac {1}{(a+b x) (d+e x)^{3/2}} \, dx}{8 (b d-a e)^4}\\ &=-\frac {7 e (4 b B d-9 A b e+5 a B e)}{20 b (b d-a e)^3 (d+e x)^{5/2}}-\frac {A b-a B}{2 b (b d-a e) (a+b x)^2 (d+e x)^{5/2}}-\frac {4 b B d-9 A b e+5 a B e}{4 b (b d-a e)^2 (a+b x) (d+e x)^{5/2}}-\frac {7 e (4 b B d-9 A b e+5 a B e)}{12 (b d-a e)^4 (d+e x)^{3/2}}-\frac {7 b e (4 b B d-9 A b e+5 a B e)}{4 (b d-a e)^5 \sqrt {d+e x}}-\frac {\left (7 b^2 e (4 b B d-9 A b e+5 a B e)\right ) \int \frac {1}{(a+b x) \sqrt {d+e x}} \, dx}{8 (b d-a e)^5}\\ &=-\frac {7 e (4 b B d-9 A b e+5 a B e)}{20 b (b d-a e)^3 (d+e x)^{5/2}}-\frac {A b-a B}{2 b (b d-a e) (a+b x)^2 (d+e x)^{5/2}}-\frac {4 b B d-9 A b e+5 a B e}{4 b (b d-a e)^2 (a+b x) (d+e x)^{5/2}}-\frac {7 e (4 b B d-9 A b e+5 a B e)}{12 (b d-a e)^4 (d+e x)^{3/2}}-\frac {7 b e (4 b B d-9 A b e+5 a B e)}{4 (b d-a e)^5 \sqrt {d+e x}}-\frac {\left (7 b^2 (4 b B d-9 A b e+5 a B e)\right ) \text {Subst}\left (\int \frac {1}{a-\frac {b d}{e}+\frac {b x^2}{e}} \, dx,x,\sqrt {d+e x}\right )}{4 (b d-a e)^5}\\ &=-\frac {7 e (4 b B d-9 A b e+5 a B e)}{20 b (b d-a e)^3 (d+e x)^{5/2}}-\frac {A b-a B}{2 b (b d-a e) (a+b x)^2 (d+e x)^{5/2}}-\frac {4 b B d-9 A b e+5 a B e}{4 b (b d-a e)^2 (a+b x) (d+e x)^{5/2}}-\frac {7 e (4 b B d-9 A b e+5 a B e)}{12 (b d-a e)^4 (d+e x)^{3/2}}-\frac {7 b e (4 b B d-9 A b e+5 a B e)}{4 (b d-a e)^5 \sqrt {d+e x}}+\frac {7 b^{3/2} e (4 b B d-9 A b e+5 a B e) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {b d-a e}}\right )}{4 (b d-a e)^{11/2}}\\ \end {align*}
________________________________________________________________________________________
Mathematica [A]
time = 1.29, size = 408, normalized size = 1.45 \begin {gather*} \frac {3 A \left (8 a^4 e^4-8 a^3 b e^3 (7 d+3 e x)+24 a^2 b^2 e^2 \left (12 d^2+17 d e x+7 e^2 x^2\right )+a b^3 e \left (85 d^3+831 d^2 e x+1239 d e^2 x^2+525 e^3 x^3\right )+b^4 \left (-10 d^4+45 d^3 e x+483 d^2 e^2 x^2+735 d e^3 x^3+315 e^4 x^4\right )\right )+B \left (8 a^4 e^3 (2 d+5 e x)-8 a^3 b e^2 \left (34 d^2+81 d e x+35 e^2 x^2\right )-4 b^4 d x \left (15 d^3+161 d^2 e x+245 d e^2 x^2+105 e^3 x^3\right )-a^2 b^2 e \left (659 d^3+1929 d^2 e x+2289 d e^2 x^2+875 e^3 x^3\right )-a b^3 \left (30 d^4+1183 d^3 e x+2457 d^2 e^2 x^2+1925 d e^3 x^3+525 e^4 x^4\right )\right )}{60 (b d-a e)^5 (a+b x)^2 (d+e x)^{5/2}}+\frac {7 b^{3/2} e (4 b B d-9 A b e+5 a B e) \tan ^{-1}\left (\frac {\sqrt {b} \sqrt {d+e x}}{\sqrt {-b d+a e}}\right )}{4 (-b d+a e)^{11/2}} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [A]
time = 0.10, size = 268, normalized size = 0.95
method | result | size |
derivativedivides | \(2 e \left (-\frac {A e -B d}{5 \left (a e -b d \right )^{3} \left (e x +d \right )^{\frac {5}{2}}}-\frac {-3 A b e +B a e +2 B b d}{3 \left (a e -b d \right )^{4} \left (e x +d \right )^{\frac {3}{2}}}-\frac {3 b \left (2 A b e -B a e -B b d \right )}{\left (a e -b d \right )^{5} \sqrt {e x +d}}-\frac {b^{2} \left (\frac {\left (\frac {15}{8} A \,b^{2} e -\frac {11}{8} B a b e -\frac {1}{2} b^{2} B d \right ) \left (e x +d \right )^{\frac {3}{2}}+\left (\frac {17}{8} A a b \,e^{2}-\frac {17}{8} A \,b^{2} d e -\frac {13}{8} B \,a^{2} e^{2}+\frac {9}{8} B a b d e +\frac {1}{2} b^{2} B \,d^{2}\right ) \sqrt {e x +d}}{\left (b \left (e x +d \right )+a e -b d \right )^{2}}+\frac {7 \left (9 A b e -5 B a e -4 B b d \right ) \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{8 \sqrt {\left (a e -b d \right ) b}}\right )}{\left (a e -b d \right )^{5}}\right )\) | \(268\) |
default | \(2 e \left (-\frac {A e -B d}{5 \left (a e -b d \right )^{3} \left (e x +d \right )^{\frac {5}{2}}}-\frac {-3 A b e +B a e +2 B b d}{3 \left (a e -b d \right )^{4} \left (e x +d \right )^{\frac {3}{2}}}-\frac {3 b \left (2 A b e -B a e -B b d \right )}{\left (a e -b d \right )^{5} \sqrt {e x +d}}-\frac {b^{2} \left (\frac {\left (\frac {15}{8} A \,b^{2} e -\frac {11}{8} B a b e -\frac {1}{2} b^{2} B d \right ) \left (e x +d \right )^{\frac {3}{2}}+\left (\frac {17}{8} A a b \,e^{2}-\frac {17}{8} A \,b^{2} d e -\frac {13}{8} B \,a^{2} e^{2}+\frac {9}{8} B a b d e +\frac {1}{2} b^{2} B \,d^{2}\right ) \sqrt {e x +d}}{\left (b \left (e x +d \right )+a e -b d \right )^{2}}+\frac {7 \left (9 A b e -5 B a e -4 B b d \right ) \arctan \left (\frac {b \sqrt {e x +d}}{\sqrt {\left (a e -b d \right ) b}}\right )}{8 \sqrt {\left (a e -b d \right ) b}}\right )}{\left (a e -b d \right )^{5}}\right )\) | \(268\) |
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: ValueError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 1305 vs.
\(2 (276) = 552\).
time = 1.21, size = 2621, normalized size = 9.33 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 609 vs.
\(2 (276) = 552\).
time = 1.03, size = 609, normalized size = 2.17 \begin {gather*} -\frac {7 \, {\left (4 \, B b^{3} d e + 5 \, B a b^{2} e^{2} - 9 \, A b^{3} e^{2}\right )} \arctan \left (\frac {\sqrt {x e + d} b}{\sqrt {-b^{2} d + a b e}}\right )}{4 \, {\left (b^{5} d^{5} - 5 \, a b^{4} d^{4} e + 10 \, a^{2} b^{3} d^{3} e^{2} - 10 \, a^{3} b^{2} d^{2} e^{3} + 5 \, a^{4} b d e^{4} - a^{5} e^{5}\right )} \sqrt {-b^{2} d + a b e}} - \frac {4 \, {\left (x e + d\right )}^{\frac {3}{2}} B b^{4} d e - 4 \, \sqrt {x e + d} B b^{4} d^{2} e + 11 \, {\left (x e + d\right )}^{\frac {3}{2}} B a b^{3} e^{2} - 15 \, {\left (x e + d\right )}^{\frac {3}{2}} A b^{4} e^{2} - 9 \, \sqrt {x e + d} B a b^{3} d e^{2} + 17 \, \sqrt {x e + d} A b^{4} d e^{2} + 13 \, \sqrt {x e + d} B a^{2} b^{2} e^{3} - 17 \, \sqrt {x e + d} A a b^{3} e^{3}}{4 \, {\left (b^{5} d^{5} - 5 \, a b^{4} d^{4} e + 10 \, a^{2} b^{3} d^{3} e^{2} - 10 \, a^{3} b^{2} d^{2} e^{3} + 5 \, a^{4} b d e^{4} - a^{5} e^{5}\right )} {\left ({\left (x e + d\right )} b - b d + a e\right )}^{2}} - \frac {2 \, {\left (45 \, {\left (x e + d\right )}^{2} B b^{2} d e + 10 \, {\left (x e + d\right )} B b^{2} d^{2} e + 3 \, B b^{2} d^{3} e + 45 \, {\left (x e + d\right )}^{2} B a b e^{2} - 90 \, {\left (x e + d\right )}^{2} A b^{2} e^{2} - 5 \, {\left (x e + d\right )} B a b d e^{2} - 15 \, {\left (x e + d\right )} A b^{2} d e^{2} - 6 \, B a b d^{2} e^{2} - 3 \, A b^{2} d^{2} e^{2} - 5 \, {\left (x e + d\right )} B a^{2} e^{3} + 15 \, {\left (x e + d\right )} A a b e^{3} + 3 \, B a^{2} d e^{3} + 6 \, A a b d e^{3} - 3 \, A a^{2} e^{4}\right )}}{15 \, {\left (b^{5} d^{5} - 5 \, a b^{4} d^{4} e + 10 \, a^{2} b^{3} d^{3} e^{2} - 10 \, a^{3} b^{2} d^{2} e^{3} + 5 \, a^{4} b d e^{4} - a^{5} e^{5}\right )} {\left (x e + d\right )}^{\frac {5}{2}}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Mupad [B]
time = 1.65, size = 418, normalized size = 1.49 \begin {gather*} \frac {\frac {35\,{\left (d+e\,x\right )}^3\,\left (-9\,A\,b^3\,e^2+4\,B\,d\,b^3\,e+5\,B\,a\,b^2\,e^2\right )}{12\,{\left (a\,e-b\,d\right )}^4}-\frac {2\,\left (A\,e^2-B\,d\,e\right )}{5\,\left (a\,e-b\,d\right )}-\frac {2\,\left (d+e\,x\right )\,\left (5\,B\,a\,e^2-9\,A\,b\,e^2+4\,B\,b\,d\,e\right )}{15\,{\left (a\,e-b\,d\right )}^2}+\frac {7\,b^3\,{\left (d+e\,x\right )}^4\,\left (5\,B\,a\,e^2-9\,A\,b\,e^2+4\,B\,b\,d\,e\right )}{4\,{\left (a\,e-b\,d\right )}^5}+\frac {14\,b\,{\left (d+e\,x\right )}^2\,\left (5\,B\,a\,e^2-9\,A\,b\,e^2+4\,B\,b\,d\,e\right )}{15\,{\left (a\,e-b\,d\right )}^3}}{b^2\,{\left (d+e\,x\right )}^{9/2}-\left (2\,b^2\,d-2\,a\,b\,e\right )\,{\left (d+e\,x\right )}^{7/2}+{\left (d+e\,x\right )}^{5/2}\,\left (a^2\,e^2-2\,a\,b\,d\,e+b^2\,d^2\right )}+\frac {7\,b^{3/2}\,e\,\mathrm {atan}\left (\frac {\sqrt {b}\,e\,\sqrt {d+e\,x}\,\left (5\,B\,a\,e-9\,A\,b\,e+4\,B\,b\,d\right )\,\left (a^5\,e^5-5\,a^4\,b\,d\,e^4+10\,a^3\,b^2\,d^2\,e^3-10\,a^2\,b^3\,d^3\,e^2+5\,a\,b^4\,d^4\,e-b^5\,d^5\right )}{{\left (a\,e-b\,d\right )}^{11/2}\,\left (5\,B\,a\,e^2-9\,A\,b\,e^2+4\,B\,b\,d\,e\right )}\right )\,\left (5\,B\,a\,e-9\,A\,b\,e+4\,B\,b\,d\right )}{4\,{\left (a\,e-b\,d\right )}^{11/2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________